If two objects travel through space along two different curves, it's often important to know whether they will collide. (will a missile hit its moving target? will two aircraft collide? ) the curves might intersect, but we need to know whether the objects are in the same position at the same time. suppose the trajectories of two particles are given by the vector functions r1(t) = t2, 6t − 5, t2 r2(t) = 9t − 20, t2, 11t − 30 for t ≥ 0. find the values of t at which the particles collide. (enter your answers as a comma-separated list. if an answer does not exist, enter dne.)

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

answer: 1+1

step-by-step explanation: 1+1 is at least 2

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches