Mathematics

Mathematics, 15.07.2019 23:10, aesthvx44

Find the vertices and foci of the hyperbola. y2 − x2 = 16 vertices (x, y) = (smaller y-value) (x, y) = (larger y-value) foci (x, y) = (smaller y-value) (x, y) = (larger y-value) find the asymptotes of the hyperbola. (enter your answers as a comma-separated list of equations.)

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Mathematics, 27.06.2019 00:30, littlebunch

Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y plus five squared divided by nine = 1.a. vertices: (-5, 3), (-5, -5); foci: (-5, -6), (-5, 4) b. vertices: (2, -5), (-4, -5); foci: (-4, -5), (2, -5) c. vertices: (3, -5), (-5, -5); foci: (-6, -5), (4, -5) d. vertices: (-5, 2), (-5, -4); foci: (-5, -4), (-5, 2)

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Mathematics, 15.07.2019 22:20, toxsicity

find the vertices and foci of the hyperbola with equation quantity x plus 5 squared divided by 81 minus the quantity of y minus 3 squared divided by 144 = 1. vertices: (4, 3), (-14, 3); foci: (-20, 3), (10, 3) vertices: (3, 7), (3, -17); foci: (3, -17), (3, 7) vertices: (7, 3), (-17, 3); foci: (-17, 3), (7, 3) vertices: (3, 4), (3, -14); foci: (3, -20), (3, 10)

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Mathematics, 19.07.2019 05:20, beatricedade48

Find the vertices and foci of the hyperbola.y2 − x2 = 9vertices (x, y) = (smaller y-value)(x, y) = (larger y-value)foci (x, y) = (smaller y-value)(x, y) = (larger y-value)

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Mathematics, 26.09.2019 04:00, ayoismeisjjjjuan

Find the vertices and foci of the hyperbola with equation quantity x plus 5 squared divided by 81 minus the quantity of y minus 3 squared divided by 144 = 1. a). vertices: (4, 3), (-14, 3); foci: (-20, 3), (10, 3) b). vertices: (3, 7), (3, -17); foci: (3, -17), (3, 7) c). vertices: (7, 3), (-17, 3); foci: (-17, 3), (7, 3) d). vertices: (3, 4), (3, -14); foci: (3, -20), (3, 10)

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Find the vertices and foci of the hyperbola. y2 − x2 = 16 vertices (x, y) = (smaller y-value) (x, y)...

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