what is the equation of the line that has a y-intercept of 5 and is parallel to
the line represented by the equation below?

A) 2x + 5

Step-by-step explanation:

First, turn 2x - y = 16 into 2x - 16 = y by adding the y on both sides and subtracting 16 from both sides.

You'll see that option A is the only option that matches the original function that we're comparing to.

Graphs will always be parallel to each other if they have the same slope, and both these functions have the same slope of 2.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.