Evaluate the following vertices for the function f(x)=x+2y

Tha values of the function f(2, 6), f(-1, 3) and f(6, 4) are 1, 5 and 14 respectively

Give the function expressed as:

f(x, y) = x + 2y

If the coordinate point is (2, 6), then;

f(2, 6) = 2 + 2(6)

f(2, 6) = 2 + 12

f(2, 6) = 14

If  the coordinate point is (-1, 3), then;

f(-1, 3) = -1 + 2(3)

f(-1, 3) = -1 + 6

f(-1, 3) = 5

If the coordinate point is (6, 4), then;

f(6, 4) = 6 + 2(4)

f(6, 4) = 6 + 8

f(6, 4) = 14

Hence the values of the function f(2, 6), f(-1, 3) and f(6, 4) are 1, 5 and 14 respectively

Learn more on function and values here: link

You might want to see if I read your ordered pairs right because it was really hard to see for me:

f(2,6)=14

f(-1,3)=5

f(6,4)=14

Step-by-step explanation:

I assume they meant to write f(x,y)=x+2y.

Doing f(2,6) now.  This means replace x with 2 and y with 6:

f(2,6)=2+2(6)=2+12=14

f(2,6)=14

Doing f(-1,3) now.  This means replace x with -1 and y with 3:

f(-1,3)=-1+2(3)=-1+6=5

f(-1,3)=5

Doing f(6,4) now. This means replace x with 6 and y with 4:

f(6,4)=6+2(4)=6+8=14

f(6,4)=14

i'm pretty sure it's 477,585,296, but perhaps my math is incorrect.

the answer

b. they are parallel and will never intersect.