One positive integer is 7 less than another. the product of two integers is 44. what are the integers?

4 and 11

Step-by-step explanation:

Lets call the smallest n

And the other one n+7

Then,

n.(n+7)=44

n²+7n=44

Subtract 44 from both sides.

n²+7n-44=44-44

n²+7n-44=0

Factorize the equation.

n²+11n-4n-44=0

n(n+11)-4(n+11)=0

(n+11)(n-4)=0

n+11=0 , n-4=0

n=-11 , n=4

n=4 is the only positive solution, so the numbers are:

4 and 11

The two integers are: 4 and 11.

Step-by-step explanation:

We are given that one positive integer is 7 less than another. Given that the product of two integers is 44, we are to find the integers.

Assuming to be one positive integer and to be the other, we can write it as:

--- (1)

--- (2)

Substituting x from (1) in (2):

y = 11

Substituting y = 11 in (1) to find x:

x = 4

6 on both sides and twelve on the top and the bottom

step-by-step explanation:

560

step-by-step explanation:

giggidy