Solve the following system. show me how you did it.

x = 3, y = 4 and z = -5.

Step-by-step explanation:

Use the elimination method:

-3x + 2y + z = -6(1)

x + 3y + 2z = 5(2)

4x + 4y + 3z = 13(3)

Multiply the first equation by -2:

6x - 4y - 2z = 12   Add this to equation (2):

7x  - y  = 17(4)

Now Multiply equation (2) by 3 and equation (3) by -2

3x + 9y + 6z = 15 (5)

-8x - 8y - 6z = -26(6)   Adding (5) + (6):

-5x + y = -11(7)

Now Add (7) and (4):

2x = 6

x = 3.

Now  substitute for x in (4):

7(3) - y = 17

-y = 17 - 21 = -4

y = 4.

Finally substitute for x and y in equation (3) to find z:

4(3) + 4(4)  +3z = 13

3z = 13 - 12 - 16 = -15

z = -5.

step-by-step explanation: i dont

i believe the correct answer is b.