After traveling steadily at 400 meters above a shipwrecked hull, a submerged vessel starts to descend when its ground distance
from the hull is 7 kilometers. what is the angle of depression for this part of the travel?
select one
o a 1.00
6.327
c 86.73
d. 88.00

Option B,

Step-by-step explanation:

Given -

The submerged vessel travel horizontal distance above the shipwrecked hull

kilometers

The vertical distance from the the shipwrecked hull to the ground is equal to kilometers

There forms a right angled triangle with

Base kilometer

Perpendicular 0.4 kilometer

Tan (angle)

Substituting the given values we get -

Angle of depression

Hence, option B is correct.

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)