Consider the following pseudocode fragment: count= 0 for i 1 to 3 for j = i+1 to 4 count= count + i - j end-for end-for 1) when i 2, how many times does the inner loop iterate? correct 2 2 check show answer the initial value of j is i+1. the final value ofj is 4. j = 3, 4. 2 iterations. 2) how many times is the variable count increased? correct 6 6 check show answer 2,3,4. when i= 2,j 3, 4. when i 3, j = 4. when i 1, a total of 6 iterations. 3) what is the final value of count? incorrect 12 the sum is over i x j, for every possible combination of i e (1,2, 3 and je 1, 2, 3, 4}, where i

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1

for a it would be 24 children.

for b i don't understand the question. is it saying for each individual person they pick 5 reds to 7 greens or is it the whole group. clarify and i hope this can you.

step-by-step explanation: