Jamie and imani each play softball. imani has won 5 fewer games than jamie. is it possible for jamie to have won 11 games if the sum of the games imani and jamie have won together is 30? yes: jamie could have won 11 games because 2x-5=30 yes: jamie could have won 11 games because 11-5 is less than 30. no: jamie could not have won 11 games because 2x-5 does not equal 30. no: jamie could not have won 11 games because 2x -11 does not equal 30.

no: jamie could not have won 11 games because 2x-5 does not equal 30

step-by-step explanation:

assume jamie won x games.

if imani won 5 fewer games than jamie, then imani won (x-5) games.

we are then given that jamie won 11 games   which implies that imani won (11-5) or 6 games.

11 games + 6 games=17.

they wanted the number of games won to be 30 and 17 isn't 30 so not possible.

so this is the answer:

no: jamie could not have won 11 games because 2x-5 does not equal 30

if you wanted your explanation to fit this answer you could say:

assume jamie won x games.

if imani won 5 fewer games than jamie, then imani won (x-5) games.

together they won (x)+(x-5)=2x-5 games.

2x-5=30

2x     =35

x       =35/2

11 is not 35/2

choice b is correct

step-by-step explanation:

we have been given the following system of linear inequalities;

we are required to graphically determine the solution to these system of inequalities. using a graphing tool, the solution is as shown in the attachment below;

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841