Mathematics

Mathematics, 12.07.2019 07:10, nicolesan3

The product of a rational and irrational number is rational

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Mathematics, 03.08.2019 03:30, dkdk31

Below is a proof showing that the sum of a rational number and an irrational number is an irrational number. let a be a rational number and b be an irrational number. assume that a + b = x and that x is rational. then b = x – a = x + (–a). x + (–a) is rational because however, it was stated that b is an irrational number. this is a contradiction. therefore, the assumption that x is rational in the equation a + b = x must be incorrect, and x should be an irrational number. in conclusion, the sum of a rational number and an irrational number is irrational. which of the following best completes the proof? it is the sum of two rational numbers. it is the sum of two irrational numbers. it represents a non-terminating, non-repeating decimal. its terms cannot be combined.

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Mathematics, 26.08.2019 07:30, yeehaw777

50) let m be a rational number and n be an irrational number. (m)(n) = c, assume c is rational mn m = c m n = c m , so n is rational, contradicting the initial assumption. the proof shows that the product of an irrational and rational number is explain. a) rational. since an irrational number cannot equal a rational number. b) irrational. since an irrational number cannot equal a rational number. c) rational. since you can write it as the division of two rational numbers. d) irrational. since you can write it as the division of two rational numbers.

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Mathematics, 18.09.2019 21:00, erickamurillo9929

Below is a proof showing that the sum of a rational number and an irrational number is an irrational number. let a be a rational number and b be an irrational number. assume that a + b = x and that x is rational. then b = x – a = x + (–a). x + (–a) is rational because however, it was stated that b is an irrational number. this is a contradiction. therefore, the assumption that x is rational in the equation a + b = x must be incorrect, and x should be an irrational number. in conclusion, the sum of a rational number and an irrational number is irrational. which of the following best completes the proof? it is the sum of two rational numbers. it is the sum of two irrational numbers. it represents a non-terminating, non-repeating decimal. its terms cannot be combined.

Answers: 1

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Mathematics, 18.10.2019 19:00, noahdwilke

Below is a proof showing that the sum of a rational number and an irrational number is an irrational number. let a be a rational number and b be an irrational number. assume that a + b = x and that x is rational. then b = x – a = x + (–a). x + (–a) is rational because however, it was stated that b is an irrational number. this is a contradiction. therefore, the assumption that x is rational in the equation a + b = x must be incorrect, and x should be an irrational number. in conclusion, the sum of a rational number and an irrational number is irrational. which of the following best completes the proof? it is the sum of two rational numbers. it is the sum of two irrational numbers. it represents a non-terminating, non-repeating decimal. its terms cannot be combined.

Answers: 3

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