Find all solutions to the equation sin(3x)cosx+sinx cos(3x)=0 on the interval [0,2pi]
a- x=0,pi/4,pi/2,3pi/4,pi,3pi/2,2pi
b- x=0,pi/2,pi,3pi/2,2pi
c- x=0,pi,2pi
d- x=0,pi/2,3pi/2

Step-by-step explanation:

Please have in mind that sin(A - B) = sin(A)cos(B) - cos(A)sin(B) 

So what we do is:

sin(3x)cos(x) - sin(x)cos(3x) = 0 => sin(3x - x) = 0 

sin(2x) = 0 

2x = 0, π, 2π, 3π, 4π 

x = 0, π/2, π, 3π/2, 2π

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)