What is the y-intercept of the line perpendicular to the line y = negative three fourthsx + 5 that includes the point (−3, −3)?
negative three fourths
1
7
negative twenty one fourths

the answer is 1

Step-by-step explanation:

1

Step-by-step explanation:

So we are given a line .  We are ask to find the y-intercept of the equation that is perpendicular to the given line and goes through the point (-3,-3).

So first step is to identify the slope of the given line which is -3/4. I was able to do this quickly because the given line is in slope-intercept form, y=mx+b.

m is the slope and b is the y-intercept.

Now a line that is perpendicular to our line is going to have the slope being the opposite reciprocal of the slope of our line.

The opposite of -3/4 is 3/4.

The reciprocal of the opposite is 4/3.

So the opposite reciprocal of -3/4 is 4/3.

So we are going to use y=mx+b to find this perpendicular line.  We already know the slope of this new line which is 4/3 and we know we want it to go through a point (x,y)=(-3,-3).  So let's enter this information and find b.  b is our final answer because the question ask for y-intercept of the perpendicular line to the given line going through (-3,-3).

Add 4 on both sides:

Simplify:

b=1

idk

step-by-step explanation: