Find the equation of the line through (6,-5) and perpendicular to the following equations. a. y=x+3 the equation of the line in slope-intercept form is (use integers or fractions for any numbers in the equation.) b. y -5x+1 the equation of the line in slope-intercept form is (use integers or fractions for any numbers in the equation.) c. x=-8 the equation of the line in slope-intercept form is (use integers or fractions for any numbers in the equation.) d. y -6 the equation of the line in slope-intercept form is (use integers or fractions for any numbers in the equation.)

this is false ^.^ lol

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

its a trick question

step-by-step explanation:

dogs love water, just turn on the hose and it will run in circles chasing the water all day : )

the bolded word " farsighted" could be replaced with visionary.