X^2=6x/(5-x)
what is the sum of the roots of the above equation?

x = 3 or x = 2 or x = 0 thus: 5

Step-by-step explanation:

Solve for x over the real numbers:

x^2 = (6 x)/(5 - x)

Cross multiply:

x^2 (5 - x) = 6 x

Expand out terms of the left hand side:

5 x^2 - x^3 = 6 x

Subtract 6 x from both sides:

-x^3 + 5 x^2 - 6 x = 0

The left hand side factors into a product with four terms:

-x (x - 3) (x - 2) = 0

Multiply both sides by -1:

x (x - 3) (x - 2) = 0

Split into three equations:

x - 3 = 0 or x - 2 = 0 or x = 0

Add 3 to both sides:

x = 3 or x - 2 = 0 or x = 0

Add 2 to both sides:

 x = 3 or x = 2 or x = 0

do you have a picture of the table

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation: