The probability that a train leaves on time is 0.8. the probability that the train arrives on time and leaves on time is 0.24. what is the probability that the train arrives on time, given that it leaves on time?

Answer is 0.3

Step-by-step explanation:

Let the probability that the train arrives on time. = p

The probability that the train leaves on time = 0.8

The probability that the train leaves on time and arrives on time = 0.24

Then the equation will be:

0.8 * p = 0.24

Move the constant value to the R.H.S

p = 0.24/0.8

p = 0.3

Thus the probability is 0.3

inverse operation of addition

3 3 6, because in every triangle the longer side is always shorter than the sum of the other two