Mathematics, 10.07.2019 04:50, dylan102247
Solve the ivp: xy' - 2xy = 10x^2, y(0) = 1 y = 3e^-2x + 2x^2 - 4 y = -3/2e^-2x + 5x + 5/2 y = 6e^2x - 5x - 5 y = 7/2e^2x - 5x - 5/2
Answers: 2
Mathematics, 28.06.2019 08:00, codeyhatch142
Answers: 1
Mathematics, 02.07.2019 01:50, alexismoore15567
Answers: 2
Mathematics, 15.07.2019 00:20, naddiachoudry9970
Answers: 2
Mathematics, 30.07.2019 06:50, emmanuelcampbel
Answers: 1
Solve the ivp: xy' - 2xy = 10x^2, y(0) = 1 y = 3e^-2x + 2x^2 - 4 y = -3/2e^-2x + 5x + 5/2 y = 6e^2x...
Mathematics, 18.03.2021 03:10
Physics, 18.03.2021 03:10
History, 18.03.2021 03:10
Mathematics, 18.03.2021 03:10