Aright pyramid with a square base has a base edge length of 12 meters and slant height of 6 meters.
the apothem is meters.
the hypotenuse of δabc is the .
the height is meters.
the volume of the pyramid is cubic meters.

Correct responses:

The given dimensions of the right pyramid having a square base are;

Base edge length, l = 12 meters

Slant height = 6·√3

Required:

Length of the apothem.

Solution:

The apothem, a, is the line drawn from the middle of the polygon to the midpoint of a side.

Therefore;

The apothem of the square base = =

Which gives;

Required:

The hypotenuse of triangle ΔABC

Solution:

The hypotenuse of ΔABC = The slant height of the square pyramid = 6·√2 meters

Therefore;

Required:

The height of the pyramid

Solution:

The height of the pyramid = The length of the side in right triangle

ΔABC, therefore, by Pythagorean theorem, we have;

= -

Which gives;

= (6·√2)² - 6² = 6²·((√2)² - 1) = 6² × 1  = 6²

= √(6²) = 6

Required:

The volume of the pyramid.

Solution:

The base area of the square pyramid, A = 12 m × 12 m = 144 m²

Therefore;

Learn more about the volume of solids here:

link

Step-by-step explanation:

Square base of the base edge = 12 meters and slant height = 6√2 meters

Apothem of the right pyramid will be = AC

1). Now AC =

AC =

     =

     = 6

Now Apothem = 6 meters

2). Hypotenuse of Δ ABC = AB = 6√2 meters

3). Height AC = 6 meters

4). Volume of the pyramid =

Volume =

             = 2×144

             = 288 meter²

option: d is correct

step-by-step explanation:

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)