What is the solution to the system of equations below? y = -3x+5 and y=4x-2 (1, 2) (1, –18) (–1, 8) (–1, –6)

(1, 2 )

Step-by-step explanation:

Given the 2 equations

y = - 3x + 5 → (1)

y = 4x - 2 → (2)

Substitute y = 4x - 2 into (1)

4x - 2 = - 3x + 5 ( add 3x to both sides )

7x - 2 = 5 ( add 2 to both sides )

7x = 7 ( divide both sides by 7 )

x = 1

Substitute x = 1 into (2) for corresponding value of y

y = (4 × 1) - 2 = 4 - 2 = 2

Solution is (1, 2 )

is there a picture

step-by-step explanation:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}