If you are given the graph of h(x)=log(6)x, how could you graph m(x)=log(6)(x+3)? translate each point of the graph of h(x) 3 units up. translate each point of the graph of h(x) 3 units down. translate each point of the graph of h(x) 3 units right. translate each point of the graph of h(x) 3 units left.

Last option: Translate each point of the graph of h(x) 3 units left.

Step-by-step explanation:

There are some transformations for a function f(x). The following is one of these transformations:

If , then the function is shifted "k" units to the left.

Given the function   and the function  , you can notice that the function m(x) is the function h(x) but shifted left 3 units.

Therefore, you could graph the function m(x) by translating each point of the graph of the function h(x) 3 units left.

This matches with the last option.

i not know

step-by-step explanation:

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: