Afootball quarterback enjoys practicing his long passes over 40 yards. he misses the first pass 40% of the time. when he misses on the first pass, he misses the second pass 20% of the time. what is the probability of missing two passes in a row?

Probability of missing two passes in a row is 0.08.

Step-by-step explanation:

Event E = A football player misses twice in a row.

P(E) = ?

Event X = Football player misses the first pass

P(X) = 0.4

Event Y = Football player misses just after he first miss

P(Y) = 0.2

Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:

P(E) = P(X).P(Y)

P(E) = 0.4*0.2

P(E) = 0.08

answer: dead jah

step-by-step explanation:

bullet + jah= dead jah

answer: its the third option.

step-by-step explanation:

i just took the test.