As quickly as possible (20pts)
find the solutions to the following linear-quadratic systems algebraically. select the ordered pair that is one of the correct solutions from among the choices below
y=x^2+3x+8
y=2x+10
a)(2,14)
b)(0,10)
,6)
d)(0,8)

  c)  (-2, 6)

Step-by-step explanation:

Subtracting the second equation from the first gives ...

  (y) -(y) = (x^2 +3x +8) -(2x +10)

  0 = x^2 +x -2 . . . . . simplify

  0 = (x -1)(x +2) . . . . factor

Solutions for x are 1 and -2. The corresponding y-values are ...

  y = 2{1, -2} +10 = {2, -4} +10 = {12, 6}

The solutions are (1, 12) and (-2, 6). The only matching choice is (-2, 6).

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