In the figure, cd = ef and ab = ce. complete the statements to prove that ab = df.
cd + de = e...
Mathematics, 08.07.2019 17:10, rosemary909
In the figure, cd = ef and ab = ce. complete the statements to prove that ab = df.
cd + de = ef + de by the property of equality.
ce = cd + de and df = ef + de by .
ce = df by the property of equality.
given, ab = ce and ce = df implies ab = df by the property of equality.
Answers: 2
Mathematics, 21.06.2019 17:30, amiechap12
Let f(x) = x+3 and g(x) = 1/x the graph of (fog)(x) is shown below what is the range of (fog)(x)?
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Mathematics, 21.06.2019 19:50, Roshaan8039
Prove (a) cosh2(x) β sinh2(x) = 1 and (b) 1 β tanh 2(x) = sech 2(x). solution (a) cosh2(x) β sinh2(x) = ex + eβx 2 2 β 2 = e2x + 2 + eβ2x 4 β = 4 = . (b) we start with the identity proved in part (a): cosh2(x) β sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 β sinh2(x) cosh2(x) = 1 or 1 β tanh 2(x) = .
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Mathematics, 21.06.2019 21:30, stichgotrich849
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