![Mathematics](/tpl/images/cats/mat.png)
Mathematics, 08.07.2019 04:10, victorialeona81
Piecewise defined function.
f(x) = {-x^2+2x+2 if
![x \leqslant - 5](/tex.php?f=x \leqslant - 5)
{-3/4x+3 if
![x > 1](/tex.php?f=x > 1)
find what f(-5) =
![answer](/tpl/images/cats/otvet.png)
Answers: 1
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Do you know the correct answer?
Piecewise defined function.
f(x) = {-x^2+2x+2 if
[tex]x \leqslant - 5[/tex]
{-3/4x+...
f(x) = {-x^2+2x+2 if
[tex]x \leqslant - 5[/tex]
{-3/4x+...
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