Find the value for tan θ given the point (-3, 4) on the terminal side. leave your answer in fraction form
find the value for sec θ given the point (-3, 4) on the terminal side. leave your answer in fraction form.

Step-by-step explanation:

The point (-3, 4) is in QII.  If we plot this point and drop an altitude then connect the point to the origin, we have a right triangle with side opposite measuring 4 units and side adjacent measuring |-3|.  The tangent of the reference angle is the ratio side opposite/side adjacent, so

Since secant is the reciprocal of cosine, let's find the cosine of the reference angle and then flip it upside down.  The cosine of the angle is the side adjacent (got it) over the hypotenuse (don't have it).  We can find the hypotenuse using Pythagorean's Theorem:

s0

and

c = 5

The cosine of the angle theta is

; therefore,

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: 48

just remember to use pemdas:

parentheses

expressions

multiplication

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