If a rectangle's length is y−2 and the width is 3y+2 write an expression for the perimeter and an expression for the area.

Area = units square.

Perimeter = 8y units.

Step-by-step explanation:

Area of a rectangle = length * width.

Perimeter of a rectangle = 2*(length + width).

It is given that length = y−2 units and width = 3y+2 units. To find the area and the area of the rectangle in terms of y, simply put the length and the width in the above area and perimeter equations.

Area = length * width = (y-2)*(3y+2).

Expanding the expression gives:

Area = 3y^2 + 2y - 6y - 4 = (3y^2 -4y - 4) units square.

Similarly,

Perimeter = 2*(length + width) = 2*(y-2 + 3y+2) = 2*4y = 8y units.

Therefore, the expression for the area and the perimeter of the given rectangle is () units square and (8y) units respectively!!!

if i put something wrong your not gonna like it so rather not say nothing.

the answer is a.

135 and 80

step-by-step explanation: