In a study of facial behavior, people in a control group are timed for eye contact in a 5-minute period. their times are normally distributed with a mean of 186.0
seconds and a standard deviation of 47.0 seconds. use the 68-95-99.7 rule to find the indicated quantity
a. find the percentage of times within 47.0 seconds of the mean of 186.0 seconds.
% (round to one decimal place as needed.)

easy its decreasing

step-by-step explanation:

because its top point is at the to of the graph on the left side (atleast from the veiw i see it) now if that top point wast in the lower part of the graph it would be increasing hope this have a nice day

step-by-step explanation:

for volume, add base x height x width

(a) {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …}

(b) $59 398

step-by-step explanation:

(a) the annual sequence of profits

aₙ = a₁rⁿ⁻¹

the model for the sequence of profits is {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …} .

(b) profit after 15 yr

  a₁ = $ 30 000

  r = 1.05

a₁₅ = 30 000 × 1.05¹⁴

a₁₅ = 30 000 × 1.979 93

a₁₅ = $59 398

the profit in year 15 will be $59 398.

the answer is

d.

5.3066 m2

step-by-step explanation: