Suppose that an observed frequency of 30 corresponds to an expected frequency of 27. compute the contribution that this observed frequency makes towards the total value of the χ² test statistic in a goodness-of-fit test or a test of independence.

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step-by-step explanation:

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870

vertical=18cm horizontal=18cm hypotenuse=25.5

step-by-step explanation: