There are 4 different methods you could use to solve a quadratic equation that would depending upon the actual equation. they are: - factoring the equation - taking the square root of both sides - completing the square - using the quadratic formula in the two equations that are listed below, describe which method would be the most appropriate to determine a solution. reference the parts of the equation to justify your response. (you do not have to solve the equation. some words/phrases to consider using in your response would be:
- factor
- foil method
- zero-product property
- standard form
- quadratic expression
- quadratic equations
- coefficient
- perfect square
part a: x^2 + 6x + 8 = 0
part b: x^2 + 6x - 11 = 0

Part A: x^2 + 6x + 8 = 0 use the factoring the equation method

Part A: x^2 + 6x + 8 = 0 use the quadratic formula

Step-by-step explanation:

Part A;

The equation is  x^2 + 6x + 8 = 0 , looking at this quadratic expression, you notice it is written in a quadratic equation standard form  of ax^2+bx+c=0. Additionally, you notice that can find what multiplied to get the quadratic equation,factor.You can identify two numbers that multiply to get ac and add to give b.In this question;

a=1,b=6,c=8

ac=8

The numbers are 4 and 2. Factoring the equation method will give;

x²+6x+8=0

x²+4x+2x+8=0

x(x+4)+2(x+4)=0

(x+2)+(x+4)=x²+6x+8

x+2=0, x=-2  and x+4=0, x=-4

Part B

The quadratic equation is ;

x²+6x-11=0

You notice that there are no factors that multiply direct to get the quadratic equation like in part 1. When you observe, a=1, b=6 and c=-11

ac=1×-11=-11 and b=6 .You notice there are no factors that multiply to give -11 and add to get 6, hence the factorizing the equation method can not be used.However, you can apply the quadratic formula that requires coefficients. You have a=1, b=c and c=-11 as the coefficients to use in the quadratic formula.

1010: 3030

is it i think