C& a manufactures treats for dogs. six samples each of five bags of treats were randomly selected and weighed, yielding the following data: bag (lbs) sample 1 2 3 4 5 1 10.2 11.8 10.1 5.9 8.6 2 8.9 11.2 12.4 7.6 5.9 3 10.6 8.8 7.6 11.3 9.9 4 9.6 6.5 12.5 10.4 6.9 5 5.9 8.6 10.3 11.8 10.1 6 12.1 7.3 5.9 10.8 11.1 what would be the control limit of a 3-sigma chart?

c& a manufactures treats for dogs. six samples each of five bags of treats were randomly selected and weighed, yielding

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)