Mathematics, 05.07.2019 02:20, hamaama

Sin2x=
a.2sinxcosx
b.1/2(cos(a-b)-cos(a+b))
c.1-2sin^2x
d.2sinx+2cosx

Answers: 2

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Sin2x=
a.2sinxcosx
b.1/2(cos(a-b)-cos(a+b))
c.1-2sin^2x
d.2sinx+2cosx...