How many integers between 1 and , inclusive, are divisible by 3 or
5 or 7?

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) =

n( divisible by 5) =

n( divisible by 7) =

n( divisible by 3 and 5) = n(3∩5)=

n( divisible by 5 and 7) = n(5∩7) =

n( divisible by 3 and 7) = n(3∩7) =

n( divisible by 3,5 and 7) = n(3∩5∩7) =

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.