Which of the following is an odd function?
f(x)= 3x^2+x
f(x)=4x^3+7
f(x)=5x^2+9
f(x)=6x^3+2x

F(x)=6x^3+2x

Step-by-step explanation:

Odd functions have solely odd powers of x.  

F(x)=4x^3+7      is actually   F(x) = 4x^3 + 7x^0, which is neither even nor odd.

F(x)=6x^3+2x   has only odd powers of x:  x^3 and x^1.  This is the answer.

Step-by-step explanation:

======================================================

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )

hope this .

r3t40