According to the american lung association 7% of the population has lung disease. of the people having lung disease 90% are smokers. of the people not having lung disease 20% are smokers. what are the chances that a smoker has lung disease?

The chances that a smoker has lung disease 25.30%.

Step-by-step explanation:

Let L is the event of the lung disease and S is the event of being smoker,

According to the question,

The probability of lung disease, P(L) = 7 % = 0.07,

⇒ The probability of not having lung disease, P(L') = 100 % - 7 % =  93 % = 0.93,

The probability of the people having lung disease who are smokers,

P(L∩S) = 90% of 0.07 = 6.3% = 0.063,

The probability of the people not having lung disease who are smokers,

P(L'∩S) = 20% of 0.93 = 18.60% = 0.186,

Thus, the total probability of being smoker, P(S) = P(L∩S) + P(L'∩S) = 0.063 + 0.186 = 0.249,

Hence, the probability that a smoker has lung disease,

( - 4 , -7 )

all the lines must parallel  

step-by-step explanation:

coordinates of c = ( - 1 , 2 )

3 units left = ( -4 , 2 )

9 units down = ( - 4 , 11 )