Aregular hexagonal prism has a height of 12 cm and base edge length of 10 cm. identify its lateral area and surface area.
l = 620 cm2 ; s = 942.6 cm2
l = 720 cm2 ; s = 1239.6 cm2
l = 720 cm2 ; s = 1759.2 cm2

  L = 720 cm² ; S = 1239.6 cm²

Step-by-step explanation:

The area of a hexagon is given by the formula ...

  A = (3/2)√3·s²

where s is the side length. Then the area of the two hexagonal bases will be ...

  base area = 3√3·(10 cm)² ≈ 519.6 cm²

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The lateral area is the product of the perimeter of the base and the height of the prism:

  L = 6×(10 cm)×(12 cm)

  L = 720 cm²

The totals surface area is the sum of lateral area and base area:

  S = L + base area = (720 +519.6) cm²

  S = 1239.6 cm²

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

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step-by-step explanation: