Solve the variable of x+9=37
also, n-5=9

x + 9 = 37

To solve for x bring 9 to the right side by subtracting 9 to both sides (what you do on one side you must do to the other). Since 9 is being added on the left side, subtraction (the opposite of addition) will cancel it out (make it zero) from the left side and bring it over to the right side.

x + 9 - 9 = 37 - 9

x + 0 = 28

x = 28

Check:

28 + 9 = 37

37 = 37

n - 5 = 9

To solve for n you must add 5 to both sides (what you do on one side you must do to the other). Since 5 is being subtracted, addition (the opposite of subtraction) will cancel it out (make it zero) from the left side and bring it over to the right side.

n - 5 + 5 = 9 + 5

n + 0 = 14

n = 14

Check:

14 - 5 = 9

9 = 9

Hope this helped!

~Just a girl in love with Shawn Mendes

x=28

n=14

Step-by-step explanation:

x+9=37

Subtract 9 from each side

x+9-9 = 37-9

x = 28

n-5=9

Add 5 to each side

n-5+5 =9+5

n = 14

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2