The roots of the equation 2×^2 + 3x -4=0 are a and b.
find the values of
a^2ß^2

4

Step-by-step explanation:

given a quadratic equation in standard form

y = ax² + bx + c = 0 : a ≠ 0

with roots α and β, then

the sum of the roots α + β = - and

the product of the roots αβ =

2x² + 3x - 4 = 0 ← is in standard form

with a = 2, b = 3 and c = - 4

αβ = = - 2, hence

α²β² = (αβ)² = (- 2)² = 4

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3