Mth 146 (maymester) 2019 6/4/19 2: 24 pm alto-3.. zakary souza & homework: homework 6, chapter 3.2 & 3.3 sign in save score: 0 of 2 pts 2 of 5 (5 complete) hw score: 66.67 % , 6 of 9 pts x 3.3.17 question solve the linear programming problem. select the corect choice below and fill in any answer boxes present in your choice. what is the maximum value of p? maximize a p p 6x+6y (type an integer or a fraction) 2x+ys 30 x+2ys 24 x, y 0 subject to o b. there is no maximum value of p more ( cick to select and enter your answerts) and then click check answer part remaining clear all 1 deroremeputcneyy

none cuz there are no "following statements" regarding the question

step-by-step explanation:

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

it would be a on edgenuit y

the diagram below is your final answer

is there supposed to be a diagram or a graph for this one? ?

step-by-step explanation: