Writ the following equation in standard form. state wether the graph of the equation is a parabola, circle, ellipse or hyperbola.
x^2+4y^2+2x-24y+33=0

x² + 4y²+ 2x - 24y + 33 = 0

= (x+1)² + 4(y-3)² - 1 - 36 + 33 = 0

= (x+1)² + 4(y-3)² = 4

= (x + 1)²/2² + (y - 3)²/1² = 1

This is an Ellipse:  C(-1,3)

The Standard Form of an Equation of an Ellipse is : (x - h)²/a²/ (y - k)²/b² = 1

where Pt(h,k) is the center. (a variable positioned to correspond with major axis)

a and b  are the respective vertices distances from center

and√a² - b²are the foci distances from center: a > b

29 is the correct answer

step-by-step explanation: