Mr. shaw graphs the function f(x) = –5x + 2 for his class. the line contains the point (-2, 12). what is the point-slope form of the equation of the line he graphed?

y - 12 = - 5(x + 2)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Given f(x) = - 5x + 2 ← in slope- intercept form with slope m = - 5

using m = - 5 and (a, b) = (- 2, 12), then

y - 12 = - 5(x - (- 2)), that is

y - 12 = - 5(x + 2) ← on point- slope form

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

d

gimmee one of those gold crowns!

~coco