Afrog (with webbed feet for sticking to a vertical surface) falls into a 6 ft deep hole with vertical sides. as the frog tries to escape, it is able to jump up 3 ft on a jump, but then slides back down 2 ft before it can jump again. if this continues, how many jumps will it take the frog to reach the top of the hole?

4

Step-by-step explanation:

Assuming that the frog is consistent with its performance, the correct answer can be calculated. It can be noticed that the ability to jump upwards is 3 feet and the sliding back down is 2 feet. This means that the gain is greater than the loss. The net gain is 1 foot for each jump. This will continue until the distance of 6 feet has been achieved. It will be: 3 ft - 2 ft = 1 ft (1 jump); 1 ft + 3 ft - 2 ft = 2 ft (2 jumps); 2 ft + 3 ft - 2 ft = 3 ft (3 jumps). At the end of the 3 jumps, the frog has already covered the distance of 3 feet. This means that when the frog jumps from this height, it will achieve the height of 6 feet, by which it will get out of the hole. This means that the frog requires 4 jumps to get out of the tunnel.

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right