How do you find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function y= -2x^2+6x-1

The vertex is:

The axis of symmetry is:

Step-by-step explanation:

For a quadratic equation of the form:

The vertex of the parabola will be the point:

In this case we have the following equation:

Note that:

Then the x coordinate of the vertex is:

Then the y coordinate of the vertex is:

The vertex is:

For a quadratic function the axis of symmetry is always a vertical line that passes through the vertex of the function.

Then the axis of symmetry is:

the circle graph is not a function.

step-by-step explanation:

the graph of the circle is not a function.

because for a graph to be a function, each value of x must give one value of y

in the circle, the values of x for -2< x< 2 each give 2 values of y.

hence this is not a function.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47