Mathematics
Mathematics, 26.06.2019 15:10, queenkimm26

For question b, do you know why you keep it at 1- a and not minus the 1 instead?


For question b, do you know why you keep it at 1- a and not minus the 1 instead?

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Mathematics, 11.07.2019 02:30, 2021andrewkell
Question 1 solve for x using the quadratic formula: x2 − 6x + 9 = 0 x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a x = 6 x = 3 x = 1 x = 0 question 2 solve: 49x2 − 60 = 0 round your answer to the nearest hundredth. x = 0 x = −3.32 and x = 3.32 x = −1.11 and x = 1.11 x = −0.82 and x = 0.82 question 3 when the solution of x2 − 9x − 6 is expressed as 9 plus or minus the square root of r, all over 2, what is the value of r? x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a 6 42 57 105 question 4 identifying the values a, b, and c is the first step in using the quadratic formula to find solution(s) to a quadratic equation. what are the values a, b, and c in the following quadratic equation? −6x2 = −9x + 7 a = 9, b = 7, c = 6 a = −9, b = 7, c = −6 a = −6, b = 9, c = −7 a = −6, b = −9, c = 7 question 5 use the quadratic formula to find the exact solutions of x2 − 5x − 2 = 0. x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a x equals 5 plus or minus the square root of 33, all over 2 x equals negative 5 plus or minus the square root of 33, all over 2 x equals 5 plus or minus the square root of 17, all over 2 x equals negative 5 plus or minus the square root of 17, all over 2 question 6 a portion of the quadratic formula proof is shown. fill in the missing statement. statements reasons x squared plus b over a times x plus the quantity b over 2 times a squared equals negative 4 times a times c all over 4 times a squared plus b squared over 4 a squared find a common denominator on the right side of the equation x squared plus b over a times x plus the quantity b over 2 times a squared equals b squared minus 4 times a times c all over 4 times a squared add the fractions together on the right side of the equation the quantity x plus b over 2 times a squared equals b squared minus 4 times a times c all over 4 times a squared rewrite the perfect square trinomial on the left side of the equation as a binomial squared x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 4 times a squared take the square root of both sides of the equation x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 2 times a simplify the right side of the equation ? subtract the quantity b over 2 times a from both sides of the equation x equals b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over a x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a x plus b over 2 times a equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a question 7 the quadratic equation 3x2 + 45x + 24 = 0 was solved using the quadratic formula, x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a. one solution is −14.45. what is the other solution? round to the hundredths place. −1.11 −0.55 0.52 14.45 question 8 the quadratic formula, x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a, was used to solve the equation. 2x2 − 8x + 7 = 0. fill in the missing denominator of the solution. 4 plus or minus the square root of 2, all over blank −16 2 4 14 question 9 identifying the values a, b, and c is the first step in using the quadratic formula to find solution(s) to a quadratic equation. what are the values a, b, and c in the following quadratic equation? −6x2 − 8x + 12 a = −6, b = −8, c = 12 a = 6, b = 8, c = 12 a = 8, b = 12, c = 0 a = −8, b = 12, c = 0
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For question b, do you know why you keep it at 1- a and not minus the 1 instead?
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