Identify an equation in slope intercept form for the line parallel to y=5x+2 that passes through (-6,-1)

y=5x+29

Step-by-step explanation:

A parallel line is going to have the same rise/run ( slope) that is what makes it parallel. Your slope is: 5/1

BUT... it is going to have a different y-intercept, that is what makes it parallel and not on top of the first line.

so...

enter your point (-6,-1) for x and y and solve for your y-intercept (z)

-1=5(-6)+z

-1=-30+z

29=z

enter that in to the slope intercept form

y=5x+29

Hope this Helps!! :)

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d