Sarah meeham blends coffee for tasti delight. she needs to prepare 160 pounds of blended coffee beans selling for $4.97 per pound. she plans to do this by blending together a high quality bean costing $6.00 per pound and a cheaper bean at $3.25 per pound. to the nearest pound, find how much high quality coffee bean and how much cheaper coffee bean she should blend

Given:
h = high quality bean ; costs 6 per pound
c = cheaper bean ; costs 3.25 per pound

160 pounds of blended coffee beans at 4.97 per pound

h + c = 160

6h + 3.25c = 160(4.97)
6h + 3.25c = 795.20

h = 160 - c

6(160-c) + 3.25c = 795.20
960 - 6c + 3.25c = 795.20
- 2.75c = 795.20 - 960 
- 2.75c = -164.80
c = - 164.80 / -2.75
c = 59.92 or 60 pounds

h = 160 - c
h = 160 - 60 
h = 100 pounds

Sarah must blend 100 pounds of high quality bean and 60 pounds of cheaper bean.

Xis equal to three