Find the solution of ivp for the differential equation (x+2)^2e^y when y(1) =0 y'= dy/dx=(x+2)^2.e^y; y(1)=0

The solution is

Step-by-step explanation:

We need to find the solution of IVP for differential equation when

Integrate both the sides with respect to dx

Since, IVP is y(1)=0

put x=1 and y=0 in above equation

add both the sides by

so,

Multiply both the sides by '-1'

Take natural logarithm both the sides,

Multiply both the sides by '-1'

Therefore, the solution is

im pretty sure its

(8,15)

step-by-step explanation:

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8