The following table shows the length (in days) of each of the 9 tucker family vacations.

based on this data, what is a reasonable estimate of the probability that the next tucker family vacation lasts less than 3 days?
choose 1

a.) 0.24

b.) 0.44

c.) 0.56

d.) 0.89

the correct answer is C

Step-by-step explanation:

Number of favorite outcomes=5

Total Number of outcomes=9

5/9 = 0.56

The probability that the next Tucker family vacation lasts less than 333 days is about 0.560.560, point, 56.

step-by-step explanation:

i think you should think about the question and not look online.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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