A. the point-slope form of the equation of a line is y ? y1 = m(x ? x1), where m is the slope and (x1, y1) is a point on the line. write the equation of the line in point-slope form perpendicular to the graph of y = 1/2x -7 passing through the point (6, 5).

b. write an equation of the perpendicular bisector of jk, where j = (? 8, 4) and k = (4, 4).

can you show work .

A.

Negative reciprocal gives you the perpendicular slope so negative reciprocal of 1/2 is -2.

Then apply point-slope form.

B. The answer is x = 6.

The midpoint of JK is

The line that goes through JK is just a horizontal line because the y-coordinate does not change. So its perpendicular bisector is the vertical line that goes through the x-coordinate of the midpoint, that is, .

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step-by-step explanation:

answer:

a=9

step-by-step explanation: lmk if you need a explanation