Write this trinomial in factored form. 3b^2+b-14

(b - 2)(3b + 7)

Step-by-step explanation:

Consider the factors of the product of the coefficient of the b² term and the constant term which sum to give the coefficient of the b- term

product = 3 × - 14 = - 42 and sum = + 1

The factors are - 6 and + 7

Use these factors to split the b- term

3b² - 6b + 7b - 14 ( factor the first/second and third/fourth terms )

= 3b(b - 2) + 7(b - 2) ← factor out (b - 2) from each term

= (b - 2)(3b + 7) ← in factored form

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: