Find the number of real number solutions for the equation. x2 + 5x + 7 = 0 0 cannot be determined 1 2

so 0 solutions.

No Real roots to this Quadratic Equation

Step-by-step explanation:

Our Quadratic equation is given as

In order to find that do we have the real roots of a quadratic equation , the Discriminant must be greater or equal to 0. The Discriminant is denoted by D and given by the formula

Where b is the coefficient of the middle term containing x, a is the coefficient of the term containing and the c is the constant term.

Hence we have

a = 1 , b = 5 and c = 7

Calculate D

Hence we see that the Discriminant (D) is less than 0, our answer is no real roots to this quadratic equation.

72 fudge and 75 toffee

step-by-step explanation:

i hope this : )

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!