Assume that adults have iq scores that are normally distributed with a mean of mu equals 100 and a standard deviation sigma equals 20. find the probability that a randomly selected adult has an iq less than 132. the probability that a randomly selected adult has an iq less than 132 is?

Step-by-step explanation:

First find the z-score.

z = (x - μ) / σ

z = (132 - 100) / 20

z = 1.6

From a z-score table:

P(z<1.6) = 0.9452

So there's a 94.52% probability that a randomly selected adult will have an IQ less than 132.

There is a 94.52% probability that a randomly selected adult has an IQ less than 132.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Assume that adults have IQ scores that are normally distributed with a mean of 100 and a standard deviation of 20. This means that .

The probability that a randomly selected adult has an IQ less than 132 is?

This probability is the pvalue of Z when . So:

has a pvalue of 0.9452.

This means that there is a 94.52% probability that a randomly selected adult has an IQ less than 132.

deez nu tz

step-by-step explanation: